What volume of air is needed for the combustion of 1 metre³ of a gas having the
following composition in percentage volume :
50% of H2,
35% of CH4,
8% of CO,
2% of C2H4,
and 5% of noncombustible admixture?
The air contains 21% (by
volume) of oxygen.
Answers
Answered by
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Holla ‼️
the volume will be directly proportional to mole
therefore interms of volume
volume of H2=.5m3
volume of CH4=.35m3
volume of co=.08m3
volume of C2H4=.06m3
equation
H2 + 1/2O2 -----H2O
CH4 + 2O2------CO2 + 2H2O
CO +1/2O2 ----CO2
C2H4 + 3O2 -----2CO2 + 2H2O
THerefore the volume of O2 required is =.25 +.7+.04+.06 m3
volume of air is.25 +.7+.04+.06 m3*100/21 =5m3
I hope it will help you ‼️
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