Question

What volume of air is needed to burn completely 100cm of propane?
C3H8(g) +502(g)--> 3CO2() + 4H20(l)

Answer 1

Explanation:

Propane burns in air according to the following equation:

C

3

H

8

+5O

2

→3CO

2

+4H

2

O.

1 mole of propane combines with 5 moles of oxygen.

Volume is directly proportional to the number of moles.

1 cm

3

of propane will combine with 5 cm

3

of oxygen.

Only 20% of air contains oxygen. So 1000 cm

3

of air contains 1000cm

3

×

100

20

=200cm

3

of oxygen.

The volume of propane that is consumed on using 1000 cm

3

of air is

5

200cm

3

=40cm

3

Answer 2

Answer:

Propane burns in air according to the following equation:

C

3

H

8

+5O

2

→3CO

2

+4H

2

O.

What volume of propane is consumed on using 1000 cm

3

of air, considering only 20% of air contains oxygen?

Explanation:

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