Question

What volume of carbon dioxide at NTP will be produced by the
reaction of 2 litres of HCl solution (sp. gravity = 1.16 and strength =
30% by weight) on excess calcium carbonate? (full process) needed​

Answer 1

Answer:

713 Litres

Explanation:

CaCO3 + 2HCl = CaCl2 + H2O + CO2

2 litres HCl   = 2× 1.16 = 2.32 kg. HCl = 2320 g HCl

from the atomic masses of chemical elements

H= 1 , CL = 35.5 ,  C = 12 , O = 16

36.5×2 g HCl gives 44g CO2

2320 g HCl gives (x) g CO2

x =  2320×44/73 = 1398 g of CO2

density of CO2 = 1.96 ×10∧-3 g/ml

volume of CO2 =  1398 g ÷1.96 ×10∧-3 g/ml = 713×10³ml = 713 L

                         = 713 Litres