what volume of carbon monoxide at 2atm and 273 degree celcius is required in order to produce 5.6 grams of metal by the reduction of ferric oxide?
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Answer:
Explanation:
Mole=given mass /molecular mass
Mole=5.6/28=.2 mole
Mole= volume in liter/22.4
.2=volume/22.4
Volume= .2×22.4=448÷100=4.48 liter
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