Question

what volume of cl2 will be obtained on heating 200 GM HCL​

Answer 1

Answer:

Limestone is essentially CaCO3; molar mass of CaCO3 = 100 g/mol

10 gm of 100% pure would be 10 gm of CaCO3

90% pure means you have only 9 gms of CaCO3 in the 10gm sample

9 gms/100gm/mol = 0.09 moles of CaCO3

When heated 1 mole of CaCO3 yields 1 moles of CO2

0.09 moles of CO3 will yield 0.09 moles of CO2

1 mole of CO2 = 22.4 liters

22.4 liters/mol x 0.09 moles = 2.016 liters