What volume of co2 is obtained at stp by heating 4g of caco3
Answers
Answered by
11
CaCO3-----> CaO+CO2
4gm of CaCO3 is given
we find no of mole of CaCO3=given weight/molar weight
=4/100=0.04 mole
because, no of mole of CaCO3 =no of mole of CO2
so, no of mole of CO2=0.04mole
now use gaseous formula
pv=nRT
v=nRT/p
=0.04. (RT/p)
now put R ,T and p value at STP
and gain answer
4gm of CaCO3 is given
we find no of mole of CaCO3=given weight/molar weight
=4/100=0.04 mole
because, no of mole of CaCO3 =no of mole of CO2
so, no of mole of CO2=0.04mole
now use gaseous formula
pv=nRT
v=nRT/p
=0.04. (RT/p)
now put R ,T and p value at STP
and gain answer
Similar questions