Question

what volume of co2 is produced on combustion of 60gm ethane [C2H6}

Answer 1

Answer:

89.6 L

Explanation:

2C2H6 + 7 O2- 4CO2 + 3H2O

C2H6 = 30amu

moles = 2 moles

So moles of CO2 = 4

At STP Vol of CO2 = 4 X 22.4 = 89.6L

Answer 2

Answer:

89.6 L

Explanation:

C2H6 + 7/2 O2 ---------> 2 CO2 + 3H2O

60 g C2H6 = 2 moles of C2H6

now 1 mole C2H6 gives 2 mole CO2

.: 2 mole C2H6 gives 4 mole CO2

= 4 X 22.4 L of CO2

= 89.6 L of CO2

~Regards