Question

what volume of Co2 will be produced by reacting 50 gram of caco3 with 0.5 moles of HCL​

Answer 1

Explanation:

equation: CaCO3 -> Ca0 + co2

1 mol Caco 3 produces I mol CO2

Molar mass calo 3 = 100 g/mol m

Mol Caco 3 in 50 g = 0.5 mol

This will produce 0.5 mol CO2

At STP . I mol CO2 has Volume = 2.4L

At STP, 0.5 mol CO2 has volume =22.4 * 0.5

. = 11.2 L