What volume of Conc. HCI will be required to prepare 0.25M HCI in a litre
Specific gravity of Conc. HCI = 1.18g/mL, % purity w/w of HCl = 36
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What is the molarity of 37% HCL?
12M (37% HCL) = 12 moles/L = 12 x 36.5 = 438 g/L = 438 mg/ml. 0.1 M x 36.5 = 3.65 g/L = 3650 mg.
Explanation:
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Answer:
12M (37% HCL) = 12 moles/L = 12 x 36.5 = 438 g/L = 438 mg/ml. 0.1 M x 36.5 = 3.65 g/L = 3650 mg.
Explanation:
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