Question

What volume of ethane (NTP; 1 bar, 273 K) is formed from 38 g of sodium propionate by fusion with sode lime?​

Answer 1

Answer:

8.87L

Explanation:

Reaction of sodium carboxylate with sodalime is called sodalime decarboxylation reaction -

Reaction is as follows:

RCH₂COONa + NaOH → RCH₃ + Na₂CO₃ (in the presence of CaO which helps in keeping NaOH dry)

According to given question,

CH₃CH₂COONa + NaOH → CH₃CH₃ + Na₂CO₃

1 mole of CH₃CH₂COONa = 1 mole of CH₃CH₃

or, 38/96 mole of CH₃CH₂COONa = 38/96 mole of CH₃CH₃

We know that at NTP, 1 mole gases occupy a volume of 22.4L

So, 38/96 mole of CH₃CH₃ will occupy a volume = 38 x 22.4/96 L = 8.87L