What volume of gas at stp would be needed to prepare 100ml of 2.5 molal (2.5m) ammonium hydroxide solution?
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SOLUTION
No. of moles= 2.5× 0.1 = 0.25
1 mole of any gas occupies 22.4 L at STP
0.25 mole occupy = 22.4/2/1× 0.25
=) 5.6L
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