What volume of h2 at stp will be consumed in obtaining 21.6 gram element boron from reduction of boron trichloride by hydrogen?
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Hello Dear.
Here is the answer---
→→→→→→→→
Chemical Equation for the Above Question will be ⇒
2BCl₃ + 3H₂ -------→ 2B + 6HCl
Molar Mass of the H₂ = 1 gram/mole.
Molar mass of the Boron = 11 grams/mole.
Mass of the Boron given = 21.6 grams.
From the Equation,
∵ 2 × 11 grams of the Boron is Produced by the 3 × 1 grams of H₂.
∴ 1 grams------------------------------------ 3/22 grams of H₂.
∴ 21.6 grams-------------------------------(3/22) × 21.6 grams of the H₂
= 2.945 grams.
We know, 1 grams of the H₂, occupies the Volume of 22.4 liter.
∴ 2.945 grams---------------------------------22.4 × 2.945
= 65.968 liter.
Thus, the Volume of the H₂ at S.T.P. is 65.968 liter.
→→→→→→→
Hope it helps.
Here is the answer---
→→→→→→→→
Chemical Equation for the Above Question will be ⇒
2BCl₃ + 3H₂ -------→ 2B + 6HCl
Molar Mass of the H₂ = 1 gram/mole.
Molar mass of the Boron = 11 grams/mole.
Mass of the Boron given = 21.6 grams.
From the Equation,
∵ 2 × 11 grams of the Boron is Produced by the 3 × 1 grams of H₂.
∴ 1 grams------------------------------------ 3/22 grams of H₂.
∴ 21.6 grams-------------------------------(3/22) × 21.6 grams of the H₂
= 2.945 grams.
We know, 1 grams of the H₂, occupies the Volume of 22.4 liter.
∴ 2.945 grams---------------------------------22.4 × 2.945
= 65.968 liter.
Thus, the Volume of the H₂ at S.T.P. is 65.968 liter.
→→→→→→→
Hope it helps.
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