What volume of hydrogen gas will be produced when 1.3 g of zinc granules react completely with excess dilute sulphuric acid at s.t.p?
Answers
Answered by
3
Answer:
Explanation:
1
mol
of
Zn
has mass of
65.39
g
.
The amount of
Zn
is
2.5
g
65.39
g/mol
=
0.038
mol
.
The amount of
H
2
produced is the same as the amount of
Zn
consumed
(
0.038
mol
)
.
1
mol
of ideal gas will occupy
22.4
L
at STP.
The
H
2
will occupy
0.038
mol
×
22.4
L/mol
=
0.86
L
.
Similar questions