Question

What volume of NH3 at stp must be passed
through 30.0 mL of 1 M H2SO4, so that the
strength of the acid reduces to 0.5 M? (molar
volume of gas at stp = 22.4 L)​

Answer 1

Answer:

2.o16lit

Explanation:

for 1milli equvivalent of H2SO4 1 milli equivalent of NH3 is used

no.of milli eq.of H2SO4 reduced by NH3 =NORMALITY×VOL(ml)

=2×1.5×30=90

no.of milli.eq.of NH3 =mass(mg) ÷ eq.mass

90=m÷17

mass of NH3 USED =1,53g

volume of NH3 used = 1.53×22400÷17=2.016lit