Question

what volume of nh3 formed when 22.4 litres of N2 combined with 6.72 litres of H2 at stp​

Answer 1

Answer:

44.8 litres

Explanation:

Moles of N2 = 22.4/24 = 0.9333 mol

N2 + 3H2 ----> 2NH3

By mole ratio, NH3 is twice as N2

NH3 = 0.9333×2 = 1.86666 mol

Volume of NH3 = 1.86666×24

= 44.8 dm³ = 44.8 litres