Question

what volume of nitrous oxide at stp will contain 1×10^24 N atoms​

Answer 1

Answer:

gram molecular mass of Nitrous oxide=14×2+16=28+16=44g

44g of Nitrous oxide=6.022×10^23

1g of nitrous oxide=6.022×10^23/44

1×10^24 g atom of Nitrous oxide=6.022×10^23/44×1×10^24

=6.022×10^47/44

=0.1368×10^47

=1.368×10^46g

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Answer 2

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