Question

what volume of oxygen at 18C and 750mm pressure can be obtained from 10g of potassium chlorate?

Answer 1

2 KClO3 = 2 KCl + 3 O2

Molar mass of KClO3 = 123g/mol

Mass of 2KClO3 = 123x2 = 246g


Molar gas volume at STP = 22.4 litres

246g of KClO3 give 3x22.4 = 67.2 litres of O2

10g would produce = (10x67.2)/246 = 2.73 littres

This is the volume that would be produced at STP

We convert it to the volume at 18C and 750mm pressure

p1 = 760, v1, 2.73, t1 = 273 K

p2 = 750, v1 = ?, t2 = 18+273 = 291K


p1v1/t1 = p2v2/t2

760x2.73/273 = 750xv2/291

v2 = 2.95 litres



2.95 litres of O2 will be produced from 10g of KClO3

Answer 2

Answer:2.95 litres of O2 will be produced from 10g of KClO3

Explanation:

2 KClO3 = 2 KCl + 3 O2

Molar mass of KClO3 = 123g/mol

Mass of 2KClO3 = 123x2 = 246g

Molar gas volume at STP = 22.4 litres

246g of KClO3 give 3x22.4 = 67.2 litres of O2

10g would produce = (10x67.2)/246 = 2.73 littres

This is the volume that would be produced at STP

We convert it to the volume at 18C and 750mm pressure

p1 = 760, v1, 2.73, t1 = 273 K

p2 = 750, v1 = ?, t2 = 18+273 = 291K

p1v1/t1 = p2v2/t2

760x2.73/273 = 750xv2/291

v2 = 2.95 litres