Question

what volume of oxygen at NTP is required to burn 36g of C4H10​

Answer 1

Answer:

Explanation:

1 mole of carbon weighs 12 grams. Hence 36 grams indicates there is 3 moles of carbon. One mole of molecular oxygen weighs 32 grams and it's volume should be 22.4 litres at STP. Hence we require 3 moles of molecular oxygen to burn completely with 3 moles of carbon

Hence we require about 22.4 x 3 = 67.2 litres of molecular oxygen.