Question

what volume of oxygen at stp is required to burn 60g of carbon completely.

Answer 1

C2H6 +72 O2 → 2 CO2 + 3 H2O30 g of ethane needs 72 = 3.5 moles of O2 1 mole of any gas occupies 22.4 L3.5 moles occupy = 3.5 × 22.4 = 78.4 LFor  60 g of ethane  need  78.430 × 60 = 156.8 L of oxygen


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