Question

what volume of oxygen at STP required to affect the combustion of 11 litres of ethylene [C2H4] at 273 degree Celsius and 380 mm of Hg pressure.

C2H4 + 3O2 => 2CO2 + 2H2O ​

Answer 1

Answer:

Given

p=380 mmHg=0.5atm

T=273°©=273+273

=546 K

V=11 litres No of moles = n

We have

PV =nRT

0.5 ×11=n×0.0821×546

n=0.5×11÷0.0821×546

=0.122 mo l

So the reaction is C2H4 + 3O2=2CO2 + 2H2O

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