What volume of oxygen gas is produced by one litre of 10 volume h2o2 at stp?
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2 H2O2 (l) ➡ O2(g) + H2O (l)2❌24 gm 22.7L at STP68gm
On the basis of above equation 22.7 litre of O2 is produced from 68 gram H2O2 at STP 10 litre of O2 at STP is produced from(68❌10)➗22.7 =29.9 gm =30 gm H2O2.
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10L of oxygen gas is produced by one liter of 10 volume H₂O₂ at STP.
- The concentration of Hydrogen peroxide solution (H₂O₂) is often described in terms of liter volume.
- The strength is in accordance with the volume of oxygen gas produced on the decomposition of H₂O₂ by the followoing reaction:
2 H₂O₂ → 2 H₂O + O₂
- When 1L of H₂O₂ solution decomposes to produce 1L of O₂ gas at STP, we say that the strength of the solution is 1 volume.
- Similarly, 1L of 10 volume H₂O₂ solution will release 10L of oxygen gas.
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