Question

What volume of oxygen gas (O₂) measured at 0°C and 1 atm, is needed to burn completely 1 L of propane gas (C₃H₈) measured under same conditions?
(A) 5 L
(B) 10 L
(C) 7 L
(D) 6 L

Answer 1

Dear Student,

◆ Answer -

(A) 5 L

● Explaination -

Combustion of propane in presence of oxygen is given by reaction -

C3H8 + 5 O2 --> 3 CO2 + 4 H2O

From the reaction, it is evident that 1 volume of propane reacts with 5 volumes of oxygen.

Hence, volume of oxygen reacting with propane = 5 × 1 L = 5 L.

Hope this helps you...