Question

What volume of oxygen gas (O2) measured at 0°c and 1 atm, is needed to burn completely 1 l of propane gas (c3h8) measured under the same condition?

Answer 1

use stoichometric

C3H8 + 5O2-----> 3CO2 + 4H2O

now u see for burning one mole of propane we wanna 5 mole of oxygen

one mole =22.4L

one mole/22.4=1L

6.022×10²³/22.4=2.68×10²²molecules

for burning 6.022×10²³ molecules ,3.01×10²⁴ molecules of oxygen

5moles of oxygen=112litre O2 wants

for burning 2.68 × 10²² ,13.4×10²³ molecules wanna

so 13.4×10²³/6.022×10²³=litre of O2/22.4
=3.0×10^25/6.022×10²³
=5 litre of O2 wants