what volume of oxygen is required for complete burning of 11.2 litres of ch4 at STP also calculate the volume of Co2 produced under the same condition
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Answer:
1mole = 22.414 litres
reaction:
CH4 + O2 = CO2 + 2H2O
11.2 LITRES = 1/2 moles
so, 1/2 moles of O2 is required
which will me 11.2 litres and 11.2 literes(1mole)
CO2 will be produced
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