what volume of oxygen is required for complete combustion of 2.2 g of propane at NTP?
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Answered by
66
Balanced equation of Combustion of propane is
C3H8 + 5O2 = 3CO2 + 4H2O
At NTP
44g of propane requires 5*22.4L of oxygen for complete combustion
2.2g of propane requires 2.2*5*22.4/44 = 5.6L
Volume of oxygen required for complete combustion is 5.6L
C3H8 + 5O2 = 3CO2 + 4H2O
At NTP
44g of propane requires 5*22.4L of oxygen for complete combustion
2.2g of propane requires 2.2*5*22.4/44 = 5.6L
Volume of oxygen required for complete combustion is 5.6L
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4
5.6L is the answer for this question
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