Question

What volume of oxygen is required for the complete combustion of propane?

Answer 1

Answer:

1L of propane required 5L of Oxygen gas.

Explanation:

C3H8 +5O2= 3CO2 +4H2O

VOLUME IS PROPORTIONAL TO MOLES

1MOLE OF PROPANE REQUIRED 5MOLE OF OXYGEN GAS

1L OF PROPANE REACT WITH 5 L OF OXYGEN

Answer 2

Answer:

22.4g is the volume of oxygen is required for the complete combustion of 8.8g propane.

Explanation:

• Propane undergoes combustion responses in a analogous fashion to other alkans.
• In the presence of redundant oxygen, propane burns to form water and carbon dioxide.
• Complete combustion of propane produces about 50 MJ/ kg of heat.
• Propane combustion is important cleaner than that of coal or unleaded gasoline.
• Number of intelligencers = mass/ molar mass
• The mass of a sample of a particular emulsion divided by the quantum of substance in that sample is called molar mass if that substance.
• Molar Mass of propane is 44.
• One operative of propane needed 5 ×22.4 litre of O2.
• Volume of oxygen = 5 ×22.4 × n
• 'n'denoted the number of intelligencers.
• For8.8 g of propane, there's0.2 intelligencers.
• therefore, n = 0.2 intelligencers
• Volume of oxygen = 5 ×22.4 ×0.2 = 22.4 g

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