Question

What volume of oxygen., measured at STP can be prepared by heating 2.16 g HgO? Write the decomposition reaction.

Answer 1

Answer:

Explanation:

2HgO -> 2Hg + O2

by their atomic masses,

   434g of mercury oxide gives 32g of O2 and 402g of mercury

by law of constant proportions,

    432g of mercury oxide gives 32g of O2 =

    13.24g of HgO give how many g of O2

   gs of O2 is 32 * 13.24/432 is approximately 0.976g

  0.976g contains 0.03 moles of oxygen

 hence vol is 0.683litre