Question

What volume of propane is burnt for every 500cm3 pf air used in the reaction under the same conditions ? (assuming oxygen is 1/5 of air ) c3h8 +5o2=3co2+4H2O

Answer 1

Hope it helps and don't forget to mark it as the brainliest answer.

Answer 2

Answer: $20cm^3$

Explanation:-

Given : Volume of air = $500cm^3$

Volume of oxygen =$\frac{1}{5}\times {\text {Volume of air}}$

Volume of oxygen =$\frac{1}{5}\times 500cm^3=100cm^3$

$C_3H_8+5O_2\rightarrow3CO_2+4H_2O$

As can be seen from the balanced equation:

1 mole of propane $C_3H_8$ uses 5 moles of Oxygen $O_2$ for complete combustion.

According to avogadro's law, 1 mole of every gas occupies 22.4 Liters or $22400cm^3$ at STP.

Thus $11200 cm^3$ of oxygen reacts with $22400cm^3$ of propane.

$100cm^3$ of oxygen will react with=$\frac{22400}{112000}\times 100=20cm^3$ of propane.