Question

what volume of so2 at room temperature and pressure is produced on heating 3 moles of zinc sulphide if reaction takes place as follows 2zns +3o2 react to form 2zno +2so2

Answer 1

Answer:

Roasting zinc sulfide ….

2ZnS(s) + 3O2(g) → 2ZnO(s) + 2SO2(g)

9.7g ……………... ………………… ?L (STP)

9.7g ZnS x (1 mol ZnS / 97.47g ZnS) x (1 mol SO2 / 1 mol ZnS) x (22.414L / 1 mol SO2) = 2.2L ………… to two significant digits

Of course, you can do this one in your head once you know the molar mass of zinc sulfide(~97g/mol). A mass of 9.7g of ZnS is about one tenth of a mole and since the mole ratio of SO2 to ZnS is 1:1, then you get about one tenth of a mole of SO2. That in turn is one tenth of 22.4L, or 2.2L to two significant digits.

Answer 2

Answer:

22.414dm3

Explanation:

this is correct are not