What volume of water should be added to 50ml of HNO3 having density 1.5g/ml and 63% by weight to have one molar solution
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In order to obtain a volume of 1 L, 500 mL of water must be added to the original solution of 500 L.
Explanation:The symbol for molarity, M, pronounced molar, has the unit mol/L.
When diluting solutions, use the equation M1V1×M2V2, where M1 is the initial molarity in mol/L, M2 is the final molarity, V1 is the initial volume in Liters, and V2 is the final volume in Liters.
Known
M1=1.0 mol/L CuSO4
V1=500mL×1L1000mL=0.5 L
M2=0.5 mol/L CuSO4
Unknown
V2
Solution
Rearrange the equation to isolate V2. Substitute the known values into the equation and solve.
V2=M1V1M2
V2=1.0mol/L×0.5L0.5mol/L=1 L
In order to obtain a volume of 1 L, 500 mL of water must be added to the original solution of 500 mL.
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