Question

what volume of water will contain 2.4 Na of neutrons ? ( where Na = Avogadro number = 6.022 × 10²³ )​

Answer 1

Answer:

this is your correct answer

Answer 2

Given: Number of neutrons: 2.4Na

To find:  volume of water that will contain 2.4 Na of neutrons

Step by step Explanation:

Number of neutrons in any atom N= M - n

M= Atomic mass

n= atomic number

• Number of neutrons in Oxygen atom = 8
• Number of neutrons in Hydrogen atom = 0
• Number of neutrons present in 1 molecule of water $(H_{2}O)$ is 8.

Neutrons present in 1 mole water = 8Na

Na = Avogadro number = 6.022 × 10²³

8 Na neurons present in = 1 mole water

1 Na neutrons will be present in = $\frac{1}{8} mole$

2.4 Na neutrons will be present in = $\frac{1}{8} \times 2.4\\=0.3 mole$

Hence, 2.4 Na neutrons will be present in 0.3 mole of water.

molecular weight of water= 18 g

number of moles of any substance is defined as the weight of the substance divided to its molecular mass of that substance.

$n = \frac{w}{M}$

w= weight of the water

M= molecular mass of water

$n = \frac{w}{M} \\0.3 = \frac{w}{18}\\w = 0.3\times 18\\w= 5.4 g$

5.4 grams of water will contain 2.4 Na of neutrons.

Density of water is 1.

5.4 grams = 5.4 mL

Hence, 5.4 mL of water will contain 2.4 Na of neutrons.