What volume of water would be added to 16.5 mL of a 0.0813 M solution of sodium borate in order to get a 0.0200 M solution?
Answers
Answered by
1
To solve this we'll need to applythe equation
M1V1 = M2V2
V1= 16.5ml
V2= ?
M1= 0.0813
M2= 0.0200
V2= (M1V1)/M2
= (0.0813*16.5)/0.0200
=67.1
volume of water = (67.1-16.5)ml
= 50.6ml
Similar questions