Question

what volume ratio of 2M and 6M solutions of HCl is to be mixed to prepare a 3M HCl solution?Ignore the change in volume due to mixing.
(A)1:2
(B)1:3
(C)3:1
(D)2:1​

Answer 1

Answer:

(C) 3:1 is the answer for your question

Explanation:

We know that

$\boxed {\text{Equivalent Molarity} = \dfrac{M_1V_1+M_2V_2}{V_1+V_2} }$

Given that,

M₁ = 2M and M₂ = 6M, Equivalent molarity = 3M

To find :

$\dfrac{V_1}{V_2}$

Solution :

Substituting the given terms in the formula, we get,

$: \longmapsto 3 = \dfrac{2V_1+6V_1}{V_1+V_2}$

$: \longmapsto 3V_1 + 3V_2 = 2V_1 + 6V_2$

$: \longmapsto V_1 = 3V_2$

$: \longmapsto \dfrac{V_1}{V_2} = \dfrac{3}{1} =3:1$

Hope it helps!!