What volume will be occupied by 8g of oxygen at stp?
Answers
Answered by
77
hey
here is your answer !!!
________________
no of moles = given mass / molar mass
now
oxygen (O2) = 16 * 2 = 32
so no of moles = 8 / 32 = 1 / 4 moles
so
volume occupied = no of moles * 22.4
= ( 1 / 4 * 22.4 ) litres
= 5.6 litres
hope it helps :)
here is your answer !!!
________________
no of moles = given mass / molar mass
now
oxygen (O2) = 16 * 2 = 32
so no of moles = 8 / 32 = 1 / 4 moles
so
volume occupied = no of moles * 22.4
= ( 1 / 4 * 22.4 ) litres
= 5.6 litres
hope it helps :)
Answered by
17
Molecular weight of oxygen = 32 g 32 g of oxygen occupies 22.4 L volume at STP 8 g of oxygen will occupy volume ...
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