What volume would be occupied by 0.15mol of carbon monoxide at rtp
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Answer:
Calculate the volume of 0.5 mol of carbon dioxide at rtp.
volume = 0.5 × 24 = 12 dm 3
Remember that 1 dm 3 = 1 000 cm 3 so the volume is also 12 000 cm 3
The equation can be rearranged to find the number of moles, if the volume of gas at rtp is known:
number of moles = volume of gas at rtp ÷ 24.
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