what volumes will 1.27 moles of helium gas occupy at stp
Answers
Answered by
6
Answer:
One mole of a gas occupies 22.4 L at STP.
1.27 mol He x (22.4 L / 1 mol) = 28.4 L.
You could also use the ideal gas law.
PV = nRT.
V = nRT / P = (1.27 mol x 0.08206 L atm / K mol x 273 K) / (1.00 atm)
= 28.4 L. __________________________________ hope it helps you.
Explanation:
mark as brainlist and follow krna plz
Similar questions