Question

What was spread in the box of baba

Answer 1

$~~~\huge\mathscr\colorbox{navy}{\color{gold}{✿Answer!}}$

$\large\sf\color{navy}{Let \: the \: side \: of \: the \: square \: be \: x. \: Then, its \: diagonal =  \sqrt{2x}^{2} = \sqrt{2x} }$

$\large\sf\color{navy}Radius \: of \: incircle = \frac{x}{2}$

$\large\sf\color{navy}Radius \: of \: circum \: circle= \sqrt{2} \times \frac{x}{2} = \frac{x}{ \sqrt{2} }$

$\large\sf\bold\color{navy}Required \: ratio = \frac{\pi {x}^{2} }{4} : \frac{\pi {x}^{2} }{2}$

$\huge\implies\color{navy} \frac{1}{4} : \frac{1}{2}= {\fbox{\color{gold}{1:2}}}$

$\color{gold}{▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬}$

$\huge\mathscr\colorbox{navy}{\color{gold}{But~what~is~the~question? }}$