What was the answer? Yesterday's paper. Ques 14. Thanks.
Attachments:
Nikitaparihar:
in that question remainder was coming
I did it wrong, so Idk. The quotient should have been x^2-4x+1. But mine was different. So yeah, doubts myself.
Mera bhai
mana pic send kr di
you can see
A) Imma girl.
B) yeah. Now that you have posted. Yup i can. Thanks.
Sorry sister
Hehe never mind.
Answers
Answered by
2
I hope it helpful for you
Attachments:
Thank you so much. P.s did you get it right in the test too? ;)
thank you
Mention not mera bhai
Not a male sapien. And did you???
okkk
Answered by
1
noLet us assume f (x) = 2x4 – 11x3 + 7x2 + 13x - 7
As (3 + √2) and (3- √2) are the zeros of the given polynomial therefore each one of (x + 3 + √2) and (x + 3 - √2) is a factor of f (x)
Consequently, [(x – (3 + √2)][(x – (3 -√2)
mark as brainliest anawer
= [(x – 3) -√2] [(x – 3) + ]
= [(x – 3)2 – 2] = x2 – 6x + 7 is a factor of f (x)
Now, on dividing f (x) by (x2 – 6x + 7) we get:

f (x) = 0
2x4 - 11x3 + 7x2 + 13x – 7 = 0
(x2 - 6x + 7) (2x2 + x – 7) = 0
(x + 3 + √2) (x + 3 -√2) (2x – 1) (x + 1) = 0
∴ x = - 3 - √2 or x = - 3 + √2 or x = 1/2 or x = - 1
Hence, all the zeros of the given polynomial are (-3 -√2), (-3 + √2), 1/2 and – 1
As (3 + √2) and (3- √2) are the zeros of the given polynomial therefore each one of (x + 3 + √2) and (x + 3 - √2) is a factor of f (x)
Consequently, [(x – (3 + √2)][(x – (3 -√2)
mark as brainliest anawer
= [(x – 3) -√2] [(x – 3) + ]
= [(x – 3)2 – 2] = x2 – 6x + 7 is a factor of f (x)
Now, on dividing f (x) by (x2 – 6x + 7) we get:

f (x) = 0
2x4 - 11x3 + 7x2 + 13x – 7 = 0
(x2 - 6x + 7) (2x2 + x – 7) = 0
(x + 3 + √2) (x + 3 -√2) (2x – 1) (x + 1) = 0
∴ x = - 3 - √2 or x = - 3 + √2 or x = 1/2 or x = - 1
Hence, all the zeros of the given polynomial are (-3 -√2), (-3 + √2), 1/2 and – 1
Similar questions