Question

what was your answer for this question? only for cbse 10th students​

Answer 1

Answer:

Step-by-step explanation:

area of the shaded region = area of the sector + area of the triangle

area of triangle

$\frac{\sqrt{3} a^{2} }{4}$

a = 14

$\frac{14^{2} \sqrt{3} }{4}$

$\frac{169\sqrt{3} }{4}$

= 84.77 -------------------- 1

area of sector =

Θ/360 $\pi$ $r^{2}$

Θ = 360-60 ( angle of an equilateral triangle is 60)

Θ = 300

300/360 × 22/7 × 7²

=128.33     ------------------2

add 1 and 2

128.33  +   84.77

213cm