Question

what weight of 60% pure sulphuricacid is required to decompose 25 gram of Chalk​

Answer 1

Answer:

CaCO3(s)+H2SO4(aq)→CaSO4(s)↓+CO2(g)↑+H2O(l)CaCO3(s)+H2SO4(aq)→CaSO4(s)↓+CO2(g)↑+H2O(l)

We knows that with respect to calcium carbonate we gots a molar quantity of….

25∙g100.09∙g∙mol−1=0.250∙mol25•g100.09•g•mol−1=0.250•mol.

For stoichiometric equivalence THE SAME molar quantity with respect to sulfuric acid, i.e. 0.250∙mol0.250•mol…i.e. a little bit less than 25∙g25•g. And so if we got 60% w/w sulfuric acid, we require 25∙g0.60=42∙g25•g0.60=42•g of the acid solution…

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