What weight of 80% pure sulphur is required to produce 64 gram of so2
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Answered by
1
Answer:
S + O2 ----------- -------------------------------------------------SO2
Now 1 mole of Oxygen gives one moles of sulphur dioxide.
5 S + 5 O2 ------------------------------------------------------------ 5 SO2
Hence it is clear from the equation that burning 5 moles of Oxygen will produce 5 moles of SO2.
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Answered by
0
S+O2 →SO2
64 kg SO2 requires 32 kg pure sulphur
We know that, 80 kg pure sulphur is present in 100 kg of sulpur sample
So 32 kg sulphur is present in
100×32
80
kg sample =40 kg
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