what weight of a sample of impure oxalic acid should be taken for titration by 0.5000 n sodium hydroxide so that the percentage of oxalic acid dehydrate will be twice the burette reading?
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weight of a sample = 1.576g
Explanation:
H2C2O4(aq) + 2 NaOH(aq) → Na2C2O4(aq) + 2 H2O(i)
This equation specifies that there are two moles of H+ supplied by each mole of oxalic acid in this reaction (since 1 mole of H+ is consumed per mole of NaOH).
Molar Mass of NaOH = 39.997
0.5000N NaOH = 0.5000M NaOH
density of NaOH = 0.5 mol/L × 39.997g/mol
density of NaOH = 19.999
density of NaOH = 19.999 + 60
density of NaOH = 79.999
Molar Mass of H2C2O4.2H2O = 126.07
weight of a sample = 126.07/79.999
weight of a sample = 1.576g
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