Question

what weight of an impure FeS sample must be taken so that the precipitate BaSO, weight obtained will be equal to half the percent of S in the sample?​

Answer 1

★CORRECT QUESTION:-

what weight of an impure FeS sample must be taken so that the precipitate BaSO4 Precipitate weight obtained will be equal to half the percent of S in the sample?

${\boxed{\underline{\tt{ \orange{Required \: \: answer \: \: is \: \: as \: \: follows:-}}}}}$

${ \sf{ \bf{ \huge{6.869g}}}}$

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★EXPLANATION:-

$: \implies \sf \pink{\% A = \frac{g_A}{g \: sample} \times 100}$

$: \implies \sf{A\%S = \frac{ \frac{1}{2} A(gBaSO4) \times \frac{S}{BaSO4}(g \frac{S}{g}BaSO4 }{g \: sample} \times 100\%}$

$: \implies \sf{1\%S = \frac{ \frac{1}{2} \times \frac{32.064}{233.40} }{g \: sample} \times 100\%}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: { \boxed{ \underline{ \color{teal}{ \sf{ \bf{g \: sample \: = 6.869g}}}}}}$