Question

what weight of Barium Chloride will react with 2.36 gram of sodium sulphate in solution so as to produce 3.88 gram of Barium sulphate and 1.94 gram of sodium chloride in solution

Answer 1

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$<b><u>Answer</u></b>$

$<b>The weight of BaCl = 3.46g</b>$

$<b><u>Step-by-step explanation</u></b>$

Let x be the weight of BaCl.

Barium chloride + sodium Sulphate ----> Barium Sulphate + Sodium chloride

BaCl + NaSO4 ------> BaCl + BaSO4 + NaCl

x + 2.36g -----> 3.88g +1.94g

x + 2.36g ------> 5.84g

x = 5.84g - 2.36g

$<b>x = 3.46g.</b>$

$<b><font color="pink">As we know, the rectant will always be equal to the product in a chemical reaction.</font></b>$

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Answer 2

x + 2.36g ----> 3.88g + 1.94g

x + 2.36g -----> 5.82g

x = 5.82g - 2.36g

x = 3.46g

The weight of the BaCl is 3.46g.