What weight of barium chloride will react with 2.36g of sodium sulphate in solution so as to produce 3.88g of barium sulphate and 1.94g of sodium chloride in solution?
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Answer:
x + 2.36g ----> 3.88g + 1.94g
x + 2.36g -----> 5.82g
x = 5.82g - 2.36g
x = 3.46g
The weight of the BaCl is 3.46g.
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