Question

what weight of Ca contains same no. of atoms as are present in 3.2 of S ?​

Answer 1

Answer:

hope it's helpful for you

Explanation:

Therefore, the mass of calcium that will contain the same number of atoms as are present in 3.2 gm of Sulphur is 4 gram.

Answer 2

Answer:

4g

Explanation:

Step I : No. of atoms in 3.2 g of sulphur

Gram atomic mass of S=32 g

32 g of sulphur atoms =6.022×10^23

3.2 g of sulphur contain atoms =[6.022×10^23/(32g)]×(3.2g)=6.022×10^22

Step II. Weight of 6.022×10^22 atoms of calcium

Gram atomic mass of Ca = 40 g

6.022×10^23 atoms of Ca weigh = 40 g

6.022×10^22 atoms of Ca weigh =[(40g)/6.022×10^23]×6.022×10^22=4g.