Question

what weight of calcium contain the same number of atoms as they are present in 2g of sulphur???( It is 2g of sulphur) Please it's urgent ​

Answer 1

Explanation:

First find number of atoms in S.

Mass = number of moles × molar mass

Number of moles = mass/molar mass

Number of moles = 3.2g/(32g/mol)

Number of moles = 0.1mol

1 mole of any substance contains avogadro number of molecules then,

Atoms = number of moles × 6.022×10^23

Atoms = 0.1 × 6.022×10^23

Atoms = 6.022×10^22

According to the question calcium also contains 6.022×10^23 atoms

Atoms = number of moles × 6.022×10^23

Atoms = mass/molar mass × 6.022×10^23

Atoms×molar mass/6.022×10^23 = mass

6.022×10^22×40/6.022×10^23 = mass

4g = mass

So 4g of calcium is answer.

Answer 2

Answer:

So 4g of calcium is answer.

Explanation:

Step I : No. of atoms in 3.2 g of sulphur

Gram atomic mass of

S = 32g

32 g of sulphur atoms

= $6.022*10^{23\\ }$

3.2 g of sulphur contain atoms

=  $\frac{6.022 *10^{23} }{32_{g} }$

Step II. Weight of

$= 6.022 * 10^{22}$

atoms of calcium

Gram atomic mass of Ca = 40 g

atoms of Ca weigh = 40 g

= $\frac{40_{g} }{6.022 * 10^{23} } * 6.022 * 10^{22} = 4_{g}$

So 4g of calcium is answer.