what weight of calcium contains the same no. of atom are present in 3.2g of sulphur
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Answered by
4
Answer:
∴ 4g of Calcium will have the same number of atoms as 3.2g of Sulphur.
Answered by
3
Answer:
32g of sulphur contains = 6.023 x 1023 atoms
So 3.2 g of sulphur contain = 6.023 x 1023 x 3.2 = 6.023x 1022 atoms
32
Mass of 6.023x 1023 atoms of Ca is 40g
Hence mass of 6.023x 1022 atoms = 6.023x 1022 x 40 = 4g
6.023x 1023
So 4g is your answer !!
Explanation:
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