Question

What weight of calcium contains the same number of atoms as they are present in 3.2g of sulphur?

Answer 1

No of moles of phosphorus = given mass / molar mass

                                      = 3.10/ 31

                                      = 0.1

No.of atoms = no. of moles x Avogadro number

                     = 0.1 x 6.022 x 10^23

                     = 6.022 x 10^22

No . of moles of sulfur = x / 32

No. of atoms = x' / 32 x 6.022 x 10^23

According to the question,

No. of atoms of sulfur = No. of atoms of phosphorus

x' / 32 x 6.022 x 10^23 = 6.022 x 10^22

Solving the equation, we get,

x'=3.2 g

There you go! Hope it helps !