Question

what weight of calcium contains the same number of atoms as are present ib 3.2 g of sulphur

Answer 1

4 g Ca contains the same no.of atoms

Answer 2

Given :

given weight of sulphur = 3.2 g

To Find :

The weight of calcium which contains same number of atoms as present in 3.2 g of sulphur

Knowledge required :

Number of moles of a given substance is calculated by ,

Number of atoms of a given substance is given by ,

[ Where N is number of atoms ,  is avogadro number and n is number of moles ]

Solution :

Given weight of sulphur = 3.2 g

Atomic weight of sulphur = 32 g/mol

Using the number of moles formulae . Number of moles of sulphur is ,

Now calculating number of atoms in given amount of sulphur ,

Avogadro number = 6.023 × 10²³

Let the weight of calcium required be x g

Atomic weight of calcium = 40 g/mol

Number of atoms in calcium is ,

Here Number of atoms in x gram of calcium is equal to the number of atoms in 3.2 g of sulphur [given].

Hence ,

4g of calcium contains same number of atoms as present in 3.2 g of Sulphur.